ikhasi

Izindaba

Indlela yokubala inani lamapayipi ensimbi ku-hexagonal bundle?

Lapho izigayo zensimbi zikhiqiza inqwaba yeamapayipi ensimbi, bawahlanganisa abe yizimo ezinezinhlangothi ezine ukuze kube lula ukuhamba nokubala. Inqwaba inamapayipi ayisithupha ohlangothini ngalunye. Mangaki amapayipi kunqwaba ngayinye?

Impendulo: 3n(n-1)+1, lapho u-n eyinombolo yamapayipi ohlangothini olulodwa lweheksagoni evamile yangaphandle. 1) * 6 = amapayipi angu-6, kanye nepayipi elilodwa phakathi nendawo.
Ukutholwa kwefomula:
Uhlangothi ngalunye luphethe amapayipi angu-n. Ungqimba olungaphandle luqukethe (n-1) * amapayipi angu-6, ungqimba lwesibili (n-2) * amapayipi angu-6, ..., ungqimba (n-1)th (n-(n-1)) * 6 = amapayipi angu-6, futhi ekugcineni ipayipi elilodwa phakathi nendawo. Isamba sithi [(n-1) + (n-2) + ... + 1]*6 + 1. Inkulumo engaphakathi kubakaki imelela isamba sokulandelana kwezibalo (isamba samatemu okuqala nesokugcina ahlukaniswe ngo-2, bese iphindaphindwa ngo-n-1 ukuze inikeze u-n*(n-1)/2).
Lokhu ekugcineni kuveza i-3n*(n-1)+1.

ithubhu

Ifomula: 3n(n-1)+1 Ukufaka u-n=8 kufomula: 3×8(8-1)+1 = 24×7+1 = 168+1 = 169 izinti


Isikhathi sokuthumela: Oct-20-2025

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